Respostas

2013-08-22T10:02:03-03:00
F = K_o.  \frac{Q_1.Q_2}{d^{2} }


Q_2 =  \frac{F.d^{2}}{K_o.Q_1}

d = 4 cm = 0,04 = 4.10^-2
k = 9.10^9
Q = microcoulomb = 10^-6


Q_2 =  \frac{0,5.4.10^{-2}.4.10^{-2}}{9.10^{9}.10^{-6}}=  \frac{8.10^{-4} }{9.10^{3}} = 0,88.10^{-7}=8,8.10^{-6}   C