Respostas

2013-08-24T15:15:37-03:00
Se Aij=12/(i+j) --> a11=12/2=6 , a12=12/(1+2)= 4 , a21= 12/3= 4 , a22= 12/(2+2)=3
--> A= [6, 4 //4, 3] com det(A)= 6·3- 4²= 18- 16= 2

--> B= A^(-1) = 1/2· [3, -4//-4, 6] = [3/2, -2 // -2, 3]

==> B+ Bt = B+ B = 2·B = [3, -4 // -4, 6]

Saludos
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