Respostas

2013-08-25T20:09:40-03:00
2x²-x-1=0

Δ = b² - 4.a.c

Δ = (-1)² - 4.(2).(-1)

Δ = 1 + 8

Δ = 9

x' = [- b + √Δ]/[2.a]

x' = [- (-1) +√9]/[2.(2)]

x' = [1 + 3]/4

x' = 1

x'' = [- b - √Δ]/[2.a]

x'' = [- (-1) - √9]/[2.(2)]

x'' = [1 - 3]/4

x'' = -1/2
4 anos atrás
1 5 1