Respostas

2013-09-03T16:58:32-03:00
Delta ... a= 1 b= -7 c= 10 

formula= b elevado a 2 - 4.a.c 
 depois baskhara 
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2013-09-03T17:00:18-03:00
Temos umas bhaskára, então temos: 
a= 1
b= -7
c= 10

x^{2} -7x +10=0

x= \frac{-(b) +-  \sqrt{ (b)^{2} -4.a.c } }{2}

x= \frac{-(-7) +-  \sqrt{ (-7)^{2} -4.(1).(10) } }{2}

x= \frac{7 +-  \sqrt{ 49 -40 } }{2}

x= \frac{7 +-  \sqrt{ 9 } }{2}

x= \frac{7 +- \sqrt{ 9 } }{2}

x= \frac{7 +- 3 }{2}

x'= \frac{7 + 3 }{2} =  \frac{10}{2} = 5

x"= \frac{7 - 3 }{2} =  \frac{4}{2} = 2

 \left \{ {{x'=5} \atop {x"=2}} \right.
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