Respostas

2013-09-04T15:08:30-03:00
P.G. = (3, 6, 12, 24, 48, 96, 192)
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2013-09-04T15:28:06-03:00
O problema nos diz que:

a_1=3\hspace{2.0cm}q=\dfrac{6}{3}=2\hspace{2.0cm}a_n=192

Aplicando a fórmula do termo geral, temos:

a_n=a_1\cdot q^{n-1}\\\\
192=3\cdot2^{n-1}\\\\
2^{n-1}=\dfrac{192}{3}\\\\
2^{n-1}=64\\\\
2^{n-1}=2^6\\\\
n-1=6\\\\
\boxed{n=7\;\text{termos}}
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