Respostas

2013-09-06T00:33:06-03:00
Cos²x+sen²x=1
(1/3)² + sen²x = 1
sen²x = 1 -1/9
sen x = raiz(8/9)
sen x = 2/3 raiz(2) = 0,94

tg x = sen x / cos x
tg x = 0,94 / (1/3) = 3*2/3 raiz(2) = 2raiz(2)

cotg x = cos x / sen x
cotg x = (1/3) / [2/3 raiz(2)] = 1/(2 raiz(2)) = raiz(2)/4

cossec x = 1/ sen x = 1/[2/3 raiz(2)] = 3/[2 raiz(2)] = 3raiz(2)/4
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