Respostas

2013-09-17T11:31:28-03:00
1)
AB = x................ BC = cat oposto = 3
seno = Cateto oposto/hipotenusa
sen 30 = 3/x
1/2 = 3/x
logo: x =6

2)
hipotenusa = 6, e cat oposto = x = AB
entao
sen 45 = x/6
 \sqrt{2} /2 = x/6
logo: x = 3 \sqrt{2}
2013-09-17T12:01:11-03:00
A)sen30°= Co/H
1/2= 3/x
x=6

b)sen 45° = CO/H
 \sqrt{2} /2 = x/6
6 \sqrt{2} =2x
2x= 6 \sqrt{2}
x=3 \sqrt{2}