Respostas

2013-10-01T17:57:00-03:00
Angulo= 60'
hipotenusa = x
cateto adjacente = 3,2
3 2 3
2013-10-01T18:15:01-03:00
Chamando o comprimento da escada de x, temos:

\cos60^{\circ}=\dfrac{3,20}{x}\\\\
\dfrac{1}{2}=\dfrac{3,20}{x}\\\\
\boxed{x=6,4\;m}
3 4 3