Respostas

2013-10-03T13:01:49-03:00
Ponto médio de AC M(AC):
 x=1+  \frac{0}{2} = \frac{1}{2}
 y=-2- \frac{1}{2}  =
 \frac{-3}{2} 


BM:
B(2, 0)
M( \frac{1}{2} ,  \frac{-3}{2} )
BM^{2} = (-2 \frac{-1}{2}) ^{2}  + (0+ \frac{3}{2}) ^{2}
B M^{2}=( \frac{3}{2})^2+( \frac{3}{2})^2
BM^{2} =  \frac{9}{4}+  \frac{9}{4}
BM^2= \frac{18}{4}
BM=  \frac{\sqrt{18} }{\sqrt{4} }= \frac{\sqrt{9}. 2}{2} =  \frac{3\sqrt{2} }{2}
5 3 5