Respostas

2013-10-03T15:01:20-03:00
 \frac{x}{3}-  \frac{(x+1)}{1} < \frac{(1-x)}{4}
 \frac{4x}{12}- \frac{(12x+12)}{12} < \frac{(3-3x)}{12}
Multiplica por 12 nos dois lados.
4x - 12x - 12 < 3-3x
-8x + 3x < 3+12
-5x<15
x< \frac{15}{-5}
x<-3
1 5 1