Respostas

2013-10-04T18:31:09-03:00
Q = m * c * /\t
2100 = 30 * c * (70 - (-20)

2100 = 30*c*90

2100 = 2700c

21/27 = c

Calor Específico
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 c = 0,78cal/g*°C (aproximadamente)
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Capacidade térmica

C = c * m
C = 0,78 * 30
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C = 23,4 cal/°C
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