Respostas

2013-10-05T11:19:28-03:00
Usa a formula \sqrt{} (x1-x2)²+(y1-y2)²=
ab= \sqrt{} (1-5)²+(1-(-2))²= \sqrt{} (4)²+(3)²= \sqrt{} 16+9=5
ac= \sqrt{} (1-5)²+(1-4)²= \sqrt{} (4)²+(3)²= \sqrt{} 16+9=5
bc=  \sqrt{} (5-5)²+(-2-4)²= \sqrt{} 0+36=6
perimetro=soma dos vertices=5+5+6=16
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