Respostas

2013-10-06T18:10:02-03:00
32-[8x+(8-2x)(4-x)] = 8
32-[8x+32-8x-8x+2x²] - 8 = 0
2x² - 8x + 8 = 0
x² - 4x + 4 = 0
x = 2
8 4 8