Respostas

2013-10-10T16:12:06-03:00
(4+3i)=(1+2i)*(m+ni)
(4+3i)=(m+ni+2mi-2n)
4+3i=(m-2n)+(2mi+ni)

m-2n=4
2m+n=3 (x2)

5m=10
m=2

2-2n=4
2n=-2
n=-1
1 5 1