Respostas

2013-10-14T14:59:23-03:00
2x- y2 = 1 (×3)
3x + y = 4 ( × (-2))       +
_____________________
6x - 3y2 = 3
-6x - 2y = - 8.           +
___________________
- 3y2 - 2y = -5.  (-1)
3y2 +2y = 5
3y2 +2y -5 =0

delta= 2^2 -4 *3* (-5)
d= 4+ 60
d= 64 
x' = -(2 + ou - v64/2*3
x'= -2+ ou -8/6
x'= -2 -8/6
x'= -10/6=>x'=5/3
x" = -2+8/6=>x"= 6/6=> x" =1
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