Respostas

2013-10-16T15:36:10-03:00
A=  \left[\begin{array}{ccc}a_{11}&a_{12}\\a_{21}&a_{22}\\a_{31}&a_{32} \end{array}\right]
aij= j^{i}
a11=1¹=1
a12=2¹=2
a21=1²=1
a22=2²=4
a31=1³=1
a32=2³=8

B=  \left[\begin{array}{ccc} b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32} &b_{33}\end{array}\right]
bij=i^{j}
b11=1¹=1
b12=1²=1
b13=1³=1
b21=2¹=2
b22=2²=4
b23=2³=8

a) a13+b21 = 2
b) b11.(a23+a31) = 1.1 = 1
1 3 1