Respostas

2013-11-02T01:23:25-02:00
1° 
( \sqrt[4]{3} )^{x}= \sqrt[3]{9}
(3^{ \frac{1}{4} })^{x}= \sqrt[3]{3^2}
(3^{ \frac{1}{4} })^{x}= 3^{ \frac{2}{3} }
\not{3}^{ \frac{1x}{4} }=\not{3}^{ \frac{2}{3} }

 \frac{1x}{4} = \frac{2}{3} ~\to~3x=8~\to~\boxed{x= \frac{8}{3}}



8^{x}=0.25\\8^{x}= \frac{25}{100} \\8^{x}= \frac{1}{4}

(2^3)^{x}=2^{-2}\\\not{2}^{3x}=\not{2}^{-2}

3x=-2~\to \boxed{x= \frac{-2}{3}}



(  \sqrt[6]{2}  )^{x}=0.5\\(  \sqrt[6]{2}  )^{x}= \frac{5}{10}

(  \sqrt[6]{2}  )^{x}= \frac{1}{2}

2^{ \frac{1x}{6} }=2^{-1}

\boxed{x=-6}
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