Respostas

2013-04-08T20:33:22-03:00

Tc/5 = (Tf-32)/9
Tc/5 = (14 -32)/9
Tc/5 = -18/9
Tc/5 = -2
Tc = -10ºC

2013-04-08T20:51:52-03:00

 

\frac{Tc}{5} = \frac{Tf - 32}{9}

 

Tc = (\frac{14 - 32}{9}) .5

 

Tc = (\frac{-18}{9}) . 5

 

Tc = -2 . 5 = Tc = -10 C