Respostas

2013-11-10T15:02:54-02:00
 \int\limits^3_0 {2+cos(x)} \, dx
 \int\limits^3_0 {2} \, dx +  \int\limits^3_0{cos(x)} \, dx 

Sendo que integral de 2 = 2x e integral de cos (x) = sen(x)

Entre o intervalo de 0 a \pi
 \int\limits^\pi_0 {2} \, dx = 2x = 2 * \pi - 2 *0 = 2 \pi
 \int\limits^\pi _0 {cos (x)} \, dx =sen (x)   = sen \pi - sen 0 = 0 - 0

Então  2\pi +0 = 2 \pi