Respostas

2013-11-11T11:50:24-02:00
Distância 1 = x
distância 2 = x+30

tg 60 = h/x
h/x = \/3

tg45 = h/(x+30)
h/(x+30) = 1
h = x+30

(x+30)/x = \/3
x+30 = x\/3
x\/3 - x = 30 
x(\/3-1) = 30
x(1,73-1) = 30
x.0,73 = 30
x = 30/0,73
x = 41,1 m