Respostas

2013-11-14T10:25:33-02:00
Z = [(10-i).i³+i^50] / (1-i)²
z = [(10-i).(-i)+i²] / (1²-2i+i²)
z = [-10i+i²+i²] / (1-2i-1)
z = [-10i-1-1] / (-2i)
z = [-10i-2] / (-2i)
z = -(10i+2) / (-2i)
z = (10i+2) / (2i)
z² = (10i+2)² / (2i)²
z² = (10i)²+40i+4 / 4i²
z² = 100.(-1) + 40i + 4 / 4i²
z² = -100 + 40i + 4 / -4
z² = -96+40i / -4
z² = 24-10i