Respostas

2013-11-13T17:32:28-02:00
Fórmula de Bhaskara:
x^3-7x^2+10x=0

/\= b^2-4ac
/\= 49-40
/\=9

x'= -(-7)+- \sqrt{9}/2* 1
x'=7+-3/2
x'=7+3/2
x'=10/2
x'= 5

x''=7-3/2
x''=4/2
x''=2