Respostas

  • Usuário do Brainly
2013-11-14T19:30:12-02:00
(2z+3i)(1-i) / (1+i)(1-i)

(2z+3i)(1-i) / (1+1)

z=bi

(2bi+3i)(1-i) / (1+1)

(2bi+3i+2b+3)/ 2

=bi+3i/2+b+3/ 2

bi+3i/2=0

b+3/2=0

b=3/2

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