Respostas

2013-11-14T22:21:31-02:00
X^2-5x+6=0
a = 1; b = - 5 e c = +6

Δ = b^2-4.a.c
Δ = 25 -24
Δ = 1

x = -b+-raiz de Δ/2
x1 = +5+1/2
x1 = 3
x2 = +5-1/2
x2 = 2

S = {2,3}
2013-11-14T22:21:50-02:00
X² - 5x + 6 = 0

Coeficientes:

a = 1
b = -5
c = 6

Raízes: 

Δ = b² - 4 a c
Δ = ( -5 )² - 4 * 1 * 6
Δ = 25 - 24
Δ = 1

x = -b ± √Δ / 2
x = - ( -5 ) ± 1 / 2

x' = 5 + 1 = 6/2 = 3
x'' = 5 -1 = 4/2 = 2

Raízes: 3 e 2.