Respostas

2013-11-17T07:51:32-02:00
C = (cij) 3*2 em que cij = 2 + i + j
C11 =(2 + 1 + 1) =4
C12 = (2 + 1 + 2) = 5
C21 = (2 + 2 + 1) = 5
C22 = (2 + 2 + 2) = 6
C31 = (2 + 3 +1) = 6
C32 = (2 + 3 + 2) = 7
4+5+5+6+6+7= 33