Respostas

2013-11-17T18:00:17-02:00
A) (6+5i)+(2-i) = 6+2+5i-i = 8+4i
b) (6-i)+(4+2i)-(5-3i) = 6-i+4+2i-5+3i = 6+4-5-i+2i+3i = 5+4i
c) 2i/3 + i - 1/2 - i + 4 - 2i = 2i+3i-6-3i+12-6i = -4i-6
15 3 15
2013-11-17T18:06:44-02:00
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4 1 4