Respostas

2013-11-17T19:26:55-02:00
x^2+2x+x+2=0
x^2+3x+2=0
Aplica Fórmula de Bhaskara:
Δ = b² -4ac

Δ = 3² -4 *1 * 2Δ = 9 -8
Δ = 1
x' = (-b + √∆)/ 2a
(-3 + 1)/2 * 1
(-3 + 1)/2
-2/2= -1
x'' = (-b - √∆)/ 2a
(-3 - 1)/2 * 1
(-3 - 1)/2
-4/2= -2
2013-11-17T19:29:35-02:00
 x^{2} +3x+2=0

delta= b2 - 4(a)(c)
delta= 9- 4(1)(2)
delta= 1

x= -b+/- raiz de delta/ 2(a)
x= -3+/- raiz de 1/ 2(1)
x= -3+/- 1/ 2
x1= -2/2= -1
x2= -4/2= -2