Respostas

2013-11-20T19:09:15-02:00
A(3, -1), B(1, 1) E(5, 5)
d(A, B) = raiz[(1-3)²+(1-(-1))²] = raiz[(-2)²+(2))²] = raiz[4 + 4] = raiz[8] = 2raiz[2]
d(A, C) = raiz[(5-3)²+(5-(-1))²] = raiz[(2)²+(6))²] = raiz[4 + 36] = raiz[40] = 4raiz[10]
d(B, C) = raiz[(5-1)²+(5-(1))²] = raiz[(4)²+(4))²] = raiz[16 + 16] = raiz[32] = 4raiz[2]


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