Respostas

2013-11-23T20:20:15-02:00
f(x)=(a-1)x2+2ax+-3
f(1)=
(a-1)1.2+2a1+-3
f(1)=(a-1)2+2a-3
f(1)=2a -2+2a-3
f(1)=4a-5
4a-5=1 
4a=1+5
4a=6
a=3/2
f(1)=4.3/2 + 5
f(1)=6 + 5
f(1)=11 
O valor máximo será 11.