Respostas

  • Ind
  • Ambicioso
2013-11-24T16:11:35-02:00
I)  x^{2} -  \frac{5x}{6} -  \frac{1}{6} = 0 ( MMC)
 6x^{2} - 5x -1 = 0 ,
 a = 6, b = -5 e c = -1 
II) Delta =  b^{2} - 4 . a . c

D =  (-5)^{2} - 4 . 6 . (-1)
\\.D = 25+ 24
D = 49


II) x = - b + \sqrt[2]{D}  / 2a
x' =  \frac{5+7}{2.6} =  \frac{12}{12} = 1

x'' =  \frac{5-7}{2.6} =  \frac{-2}{12} =  \frac{-1}{6}