Respostas

2013-11-29T01:48:21-02:00
A=-3
B=-2
C=3

Δ= B²-4AC
Δ=(-2)²-4.(-3).3
Δ=4+36
Δ=40
X=  \frac{-B+-√Δ}{2A}
X=  \frac{-(-2)+-√40}{2(-3)}
X=  \frac{4+-4√10}{-6}
X'= - \frac{2-2√10}{3)}
X''= - \frac{2+2√10}{3)}