Respostas

2013-12-01T03:24:04-02:00
(x+3)² + (y-4)² = 1
x² + 6x + 9  +  y²- 8y + 16 = 1
x² + y² + 6x - 8y + 9 + 16 - 1 = 0
 \boxed{x^{2} + y^{2} +6x-8y+24=0}

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