Respostas

2013-12-06T19:57:08-02:00
Mmc (1-m) e m = (1-m).m
(1-m).m:(1-m).m + (1-m).m:m .(m-2) = (1-m).m . 1
m²+(1-m).(m-2) = (1-m).m
m²+m-2-m²+2m = m-m²
m²-m²+m+2m-2-m+m² = 0
m²+2m-2 = 0
Δ = (2)² - 4.1.(-2)
Δ = 4+8
Δ = 12
m = (-b+/-\/Δ)/2a
m = (-2+/-\/12)/2
m = (-2+/-2\/3)/2
m' = (-2+2\/3)/2 --> m' = -1+\/3
m" = (-2-2\/3)/2 --> m" = -1-\/3