Respostas

2013-12-08T08:28:01-02:00
log[a] b = x⇒ b=a^x ⇒[a] 
log(a) b=log b/log a 
log a/b=log a-log b
log a*b=log a+log b
b*log a= log a^b
(1/b)*log a= log a^(1/b)
log 10 =1, pois 10^1=10
log 5= log10/2=log 10 - log 2=1-log 2
log a = - colog a
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