Respostas

2013-12-16T11:08:02-02:00
Dada a função polinomial p(x) = 2x3 + 2x2 – 5x + 1. Determine os pares ordenados quando:
x = 0
p(x) = 2x3 + 2x2 – 5x + 1
p(0) = 2*03 + 2*02 – 5*0 + 1
p(0) = 0 + 0 – 0 + 1
p(0) = 1
par ordenado (0,1)

x = 1
p(1) = 2*13 + 2*12 – 5*1 + 1
p(1) = 2 + 2 – 5 + 1
p(1) = 0
par ordenado (1,0)

x = 2
p(2) = 2*23 + 2*22 – 5*2 + 1
p(2) = 2*8 + 2*4 – 10 + 1
p(2) = 16 + 8 – 10 + 1
p(2) = 15
par ordenado (2,15)
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