Respostas

2013-12-17T17:28:44-02:00
2013-12-17T17:40:01-02:00
x²-5x+6=0
a= 1 b= -5 c=6
Δ= b²-4ac
Δ= (-5)² - 4·1·6
Δ=25-24
Δ= 1

x= -b +/- √Δ/ 2a
x= - (-5) +/- √1/2
x= -5+/- 1/2

x'= 3
x''= 2

Obtêm-se 2 e 3.