Respostas

2013-12-22T18:46:26-02:00
PG : [6,a_2,a_3,a_4,a_5,192] 

a_1= 6 , a_6 = 192 

a_n=a_1. q^{n-1} ==> a_6=a_1.q^{5} 

192 = 6.q^5 ==> q^5 = \frac{192}{6} = 32 </span>\\<span>[tex]q^5 = 32 ==> q^5 = 2^5 ==> q = 2 

Logo , a_2 = a_1 × 2 = 6 × 2 = 12 

a_3 = a_2 × 2 = 12 × 2 = 24 

a_4 = a_2 × 2 = 24 × 2 = 48 

a_5 = 48 × 2 = 96 

Portanto , a PG será :

PG => ( 6 , 12 , 24 , 48 , 96 , 192 )
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