Respostas

2014-01-05T13:30:46-02:00
Xv= \frac{-b}{2.a} \\\\Xv= \frac{-(-2)}{2.1}\\\\Xv= \frac{2}{2}\\\\\boxed{Xv= 1}

\Delta=b^2-4.a.c\\\Delta=(-2)^2-4.1.(-3)\\\Delta=4+12\\\boxed{\Delta=16}

Yv= \frac{-\Delta}{4.a} \\\\Yv= \frac{-16}{4.1}\\\\Yv= \frac{-16}{4}\\\\\boxed{Yv= -4}

As coordenadas do vértice são:
V=(Xv,~Yv)\\\\\boxed{V=(1,~-4)}