Respostas

2014-01-06T18:42:00-02:00
(c_{ij})_{3x3}
(c_{ij})=  \left \{ {{1, se i=j} \atop {i^2, se i \neq j}} \right.

c₁₁= 1
c₁₂= 1²=1
c₁₃= 1²=1

c₂₁= 2²=4
c₂₂= 1
c₂₃= 2^²=4

c₃₁= 3²=9
c₃₂=3²=9
c₃₃= 1

 (c_{ij})\left[\begin{array}{ccc}1&1&1\\4&1&4\\9&9&1\end{array}\right]


(d_{ij})_{3x3} \\ \\(c_{ij})= \left \{ {{1+j, se i \neq j} \atop {i-3j, se i = j}} \right. 


d₁₁= 1-3(1)= -2
d₁₂= 1+2=3
d₁₃= 1+3=4

d₂₁= 1+1=2
d₂₂= 2-3(2)= -4
d₂₃= 1+3=4

d₃₁= 1+1=2
d₃₂=1+2=3
d₃₃= 3-3(3)= -6

(d_{ij})  \left[\begin{array}{ccc}-2&3&4\\2&-4&4\\2&3&-6\end{array}\right]