Respostas

2014-01-08T20:49:50-02:00
Primeiro tem que fatorar o 36, fatorando fica: 2.2.3.3

log36 \\\\ log(2.2.3.3) \\\\ log2+log2+log3+log3\\\\0,30+0,30+0,48+0,48=\boxed{1,55}
2 3 2
2014-01-08T20:50:29-02:00
Log 36 =
log 6² =
2 log 6 =
2 log (2 * 3) =
2 * (log 2 +log3) =
2 * (0,30 + 0,48)   =
1,56
1 5 1