Respostas

2014-01-09T22:49:48-02:00
1/2a+2/3a-1/2c+1/3c = 
mmc 2a,3a,2c,3c = 6ac
(6ac:2a.1)/(6ac) + (6ac:3a.2)/(6ac) - (6ac:2c.1)/(6ac) + (6ac:3c.1)/(6ac) = 
(3c)/(6ac) + (4c)/(6ac) - (3a)/(6ac) + (2a)/(6ac) = 
(3c+4c-3a+2a)/(6ac) = (7c-a)/(6ac)
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