Respostas

2014-01-10T15:09:32-02:00
x^2-3x+4=0\\\\a=1\\b=-3\\c=4\\\\Xv= \frac{-b}{2.a}\\\\Xv= \frac{-(-3)}{2.1}\\\\\boxed{Xv= \frac{3}{2}}\\\\\\\Delta=b^2-4.a.c\\\Delta=(-3)^2-4.1.4\\\Delta=9-16\\\Delta=-7

Yv= \frac{-\Delta}{4.a}\\\\ Yv= \frac{-(-7)}{4.1}\\\\ \boxed{Yv= \frac{7}{4}}

As coordenadas do Vértice são:

\boxed{V=(~~ \frac{3}{2}~,~ \frac{7}{4} ~~)}

Espero ter ajudado.. :)