Respostas

2014-01-10T17:05:05-02:00
23ºF - 86ºF

 \frac{TC}{100} = \frac{tf-32}{180}

 \frac{tc}{100} = \frac{23-32}{180}

 \frac{tc}{100} =  \frac{-9}{180}

tc.180 = (-900)

tc =  \frac{-900}{180}
tc'=-5ºC


 \frac{tc}{100} =  \frac{54}{180}

tc=  \frac{5400}{180}

tc"= 30ºC

Δtc= tc"-tc'
Δtc=30- (-5)
Δtc=35ºC

:D