Respostas

2014-01-11T01:14:04-02:00
Calculando o vértice de x²-4 x+3 = 0
Xv= \frac{-b}{2.a} \\\\Xv= \frac{-(-4)}{2.1}\\\\Xv= \frac{4}{2}\\\\\boxed{Xv=2}

\Delta=b^2-4.a.c\\\Delta=(-4)^2-4.1.3\\\Delta=16-12\\\Delta=4

Yv= \frac{-\Delta}{4.a} \\\\Yv= \frac{-4}{4.1}\\\\\boxed{Yv=-1}

V=(Xv,~Yv)\\\\\boxed{\boxed{V=(2,~-1)}}

Espero ter ajudado.


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