Respostas

2014-01-13T20:33:41-02:00
log_{b}(a)=c <=> b^{c}=a
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log_{2}[log_{(1/2)}(x)]=0
2^{0}=log_{(1/2)}(x)
1=log_{(1/2)}(x)
log_{(1/2)}(x)=1
(1/2)^{1}=x
x=1/2
1 5 1