Respostas

2013-04-23T17:49:18-03:00

Sec x = 7/3
logo    1/Cosx = 7/3
Cosx = 3/7
cos²x + sen²x = 1
9/49 + sen²x = 1
sen² = 40/49
sen = - 2\sqrt{10} /49
tgx = senx/cosx
tgx = ( - 2\sqrt{10} /49)/(3/7)
tgx = - 2\sqrt{10} / 21

Cotgx = 1/tgx
cotgx = - 21 /  2\sqrt{10}
15m/10 =  - 21 /  2\sqrt{10}

m = \frac{-7}{\sqrt{10}}

 

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