Respostas

2014-02-01T23:04:19-02:00
olá

3x² -4+9x=5+6x-2
3x² +3x-7=
Δ=b²-4.a.c
Δ=9-4.3.-7
Δ=9+84
Δ=93


x1= -b+√Δ/2.a
x1=-3+√93/6
x2=-3-√93/6

S=(-3+√93)/6,-3-√93/6)

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