Respostas

  • Usuário do Brainly
2013-01-10T21:03:34-02:00

Façamos \text{A}=\{4+2\cdot[32-\frac{1}{4}\left(\frac{2}{3}-\dfrac{1}{8}\right)+2]+16\}+1

 

Desta maneira, temos:

 

\text{A}=\{4+2\cdot[32-\frac{1}{4}\cdot\dfrac{13}{24}+2]+16\}+1

 

\text{A}=\{4+2\cdot[32-\frac{13}{96}+2]+16\}+1

 

\text{A}=\{4+2\cdot[\frac{3~072}{96}+2]+16\}+1

 

\text{A}=\{4+2\cdot34+16\}+1

 

\text{A}=88+1=89

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