Respostas

2014-02-25T19:35:24-03:00
X² = 2x - 1
x² - 2x + 1 = 0
Δ = b² - 4ac
Δ = (-2)² - 4·1·1
Δ = 4 - 4
Δ = 0
x = (2 +ou- √0) ÷2
x = (2+0) ÷ 2
x = 1
ou
x= (2-0) ÷2
x = 1