Respostas

2014-03-03T12:12:02-03:00
F(x)=ax+b
f(3)=5
f(-2)=-5

f(3)=a.3+b
5=3a+b

f(-2)=a.(-2)+b
-5=-2a+b
 \left \{ {{3a+b=5} \atop {2a+b=-5}} \right. (-1)
 \left \{ {{3a+b=5} \atop {+2a-b=5}} \right.
5a=10
a=10/5
a=2

3a+b=5
3.2+b=5
b=5-6
b=-1

f(1/2)=2.1/2+(-1)
f(0,5)=2.0,5-1
f(0,5)=1-1
f(1/2)=0